Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions)
In an adiabatic process, R = 2/3 Cv. The pressure of the gas will be proportional to :
29
Oct
In an adiabatic process, R = 2/3 Cv. The pressure of the gas will be proportional to : In an adiabatic process R = 2/3 Cv. The pressure of the gas will be proportional to : October 29, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,
The molar specific heat of oxygen at constant pressure Cp = 7.03 cal/mol C and R = 8.31 J/mol C. The amount of heat taken by 5 mol of oxygen when heated at constant volume
29
Oct
The molar specific heat of oxygen at constant pressure Cp = 7.03 cal/mol C and R = 8.31 J/mol C. The amount of heat taken by 5 mol of oxygen when heated at constant volume The molar specific heat of oxygen at constant pressure Cp = 7.03 cal/mol C and R = 8.31 J/mol C. [...]
Five Styrofoam balls are suspended from insulating threads. Several experiments are performed on the balls and the following observations are made: (i) Ball A repels C and attracts B. (ii) Ball D attracts B and has no effect on E. (iii) A negatively charged rod attracts both A and E. An electrically neutral Styrofoam ball gets attracted if placed nearby a charged body due to induced charge. What are the charges, if any, on each ball A,B,C,D, and E?
29
Oct
Five Styrofoam balls are suspended from insulating threads. Several experiments are performed on the balls and the following observations are made: (i) Ball A repels C and attracts B. (ii) Ball D attracts B and has no effect on E. (iii) A negatively charged rod attracts both A and E. An electrically neutral Styrofoam ball [...]
A point charge +Q is placed at the centroid of an equilateral triangle. When second charge +Q is placed at the vertex of the triangle the magnitude of the electrostatic force on the central charge is 8N. The magnitude of the net force on the central charge when a third charge +Q is placed at another vertex of the triangle is
29
Oct
A point charge +Q is placed at the centroid of an equilateral triangle. When second charge +Q is placed at the vertex of the triangle the magnitude of the electrostatic force on the central charge is 8N. The magnitude of the net force on the central charge when a third charge +Q is placed at [...]
A large sheet carries uniform surface charge density σ . A rod of length 2l has a linear charge density lamba on one half and −λ on the second half. The rod is hinged at the midpoint O and makes an angle θ with the normal to the sheet. The torque experience by the rod is
29
Oct
A large sheet carries uniform surface charge density σ . A rod of length 2l has a linear charge density lamba on one half and −λ on the second half. The rod is hinged at the midpoint O and makes an angle θ with the normal to the sheet. The torque experience by the rod [...]
Find the force experienced by a semicircular rod having a charge q as shown in fig. Radius of the wire is R, and the line of charge with linear charge density λ passes through its center and is perpendicular to the plane of wire.
29
Oct
Find the force experienced by a semicircular rod having a charge q as shown in fig. Radius of the wire is R, and the line of charge with linear charge density λ passes through its center and is perpendicular to the plane of wire. and the line of charge with linear charge density λ passes [...]
The equation of state for a gas is given by PV = nRT + alpha V, where n is the number of moles and alpha a positive constant. The initial pressure and temperature of 1 mol of the gas
29
Oct
The equation of state for a gas is given by PV = nRT + alpha V, where n is the number of moles and alpha a positive constant. The initial pressure and temperature of 1 mol of the gas The equation of state for a gas is given by PV = nRT + alpha V [...]
The direction ( theta ) of E at point P due to uniformly charged finite rod will be
29
Oct
The direction ( theta ) of E at point P due to uniformly charged finite rod will be The direction ( theta ) of E at point P due to uniformly charged finite rod will be October 29, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,
An ideal gas (gama = 1.5) is expanded adiabatically. How many times has the gas to be expanded to reduce the root-mean-square velocity of molecules becomes half ?
29
Oct
An ideal gas (gama = 1.5) is expanded adiabatically. How many times has the gas to be expanded to reduce the root-mean-square velocity of molecules becomes half ? An idea gas (gama = 1.5) is expanded adiabatically. How many times has the gas to be expanded to reduce the root-mean-square velocity of molecules becomes half [...]
An ideal gas expands isothermally from volume V1 to V2 and is then compressed to original volume V1 adiabatically. Initial pressure is P1 and final pressure is P3. The total work done is W.
29
Oct
An ideal gas expands isothermally from volume V1 to V2 and is then compressed to original volume V1 adiabatically. Initial pressure is P1 and final pressure is P3. The total work done is W. An ideal gas expands isothermally from volume V1 to V2 and is then compressed to original volume V1 adiabatically. Initial pressure [...]