Chapter 6 – Gravitation
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Two cars of mass m1andm2 are moving in circle of radii r1andr2 , respectively . Their speeds are such that they make complete circles in the same time t . The ratio of their centripetal acceleration is :
19
Sep
Two cars of mass m1andm2 are moving in circle of radii r1andr2 , respectively . Their speeds are such that they make complete circles in the same time t . The ratio of their centripetal acceleration is : respectively . Their speeds are such that they make complete circles in the same time t . [...]
The variation of acceleration due to gravity g with distance d from centre of the earth is best represented by (R=Earth’s radius) :
19
Sep
The variation of acceleration due to gravity g with distance d from centre of the earth is best represented by (R=Earth’s radius) : The variation of acceleration due to gravity g with distance d from centre of the earth is best represented by (R=Earth's radius) : September 19, 2020 Category: Chapter 6 - Gravitation , [...]
Two satellites, A and B, have masses m and 2m respectively. A is in circular orbit of radius R, and B is in a circular orbit of radius 2R around the earth. The ratio of their kinetic energies, TA/TB is:
19
Sep
Two satellites, A and B, have masses m and 2m respectively. A is in circular orbit of radius R, and B is in a circular orbit of radius 2R around the earth. The ratio of their kinetic energies, TA/TB is: A and B and B is in a circular orbit of radius 2R around the [...]
A straight rod of length L extends from x=a to x=L +a. The gravitational force is exerted on a point mass ‘m’ at x=0, if the mass per unit length of the rod is A+Bx^2 is given by.
19
Sep
A straight rod of length L extends from x=a to x=L +a. The gravitational force is exerted on a point mass ‘m’ at x=0, if the mass per unit length of the rod is A+Bx^2 is given by. A straight rod of length L extends from x=a to x=L +a. The gravitational force is exerted [...]
A satellite is revolving in a circular orbit at a height h from the earth surface such that h
19
Sep
A satellite is revolving in a circular orbit at a height h from the earth surface such that h A satellite is revolving in a circular orbit at a height h from the earth surface such that h September 19, 2020 Category: Chapter 6 - Gravitation , JEE Mains Physics 2002-2019 Solved Video Solutions ,
Two stars of masses 3×10^31 kg each, and at distance 2×10^11 m rotate in a plane about their common centre of mass O. A meteorite passes through O moving perpendicular to the star’s rotation plane. In order to escape from the gravitational field of this double star, the minimum speed that meteorite should have at O is : (take Gravitational constant G=6.67×10^11Nm 2kg^−2 )
19
Sep
Two stars of masses 3×10^31 kg each, and at distance 2×10^11 m rotate in a plane about their common centre of mass O. A meteorite passes through O moving perpendicular to the star’s rotation plane. In order to escape from the gravitational field of this double star, the minimum speed that meteorite should have at [...]
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A rocket has to be launched from earth in such a way that it never returns. If E is the minimum energy delivered by the rocket launcher ,
A source of sound is approaching an observer with speed of 30ms and the observer is approaching the source with a speed 60 ms". Then the fractional change in the frequency of sound in air (330ms) is ,
Two stars of masses 3×10^31 kg each ,
The energy required to take a satellite to a height h above Earth surface ( radius of Earth = 6.4×10^3 km) is E1 and kinetic energy required for the satellite to be in a circular orbit at this height is E2. The value of h for which E1 and E2 are equal, is:
19
Sep
The energy required to take a satellite to a height h above Earth surface ( radius of Earth = 6.4×10^3 km) is E1 and kinetic energy required for the satellite to be in a circular orbit at this height is E2. The value of h for which E1 and E2 are equal, is: A rocket [...]
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A rocket has to be launched from earth in such a way that it never returns. If E is the minimum energy delivered by the rocket launcher ,
A source of sound is approaching an observer with speed of 30ms and the observer is approaching the source with a speed 60 ms". Then the fractional change in the frequency of sound in air (330ms) is ,
The ratio of the weights of a body on the Earth’s surface to that on the surface of a planet is 9:4. The mass of the planet is 9/1 th of that of the Earth. If ‘R’ is the radius of the Earth, what is the radius of the planet ? (Take the planets to have the same mass density)
19
Sep
The ratio of the weights of a body on the Earth’s surface to that on the surface of a planet is 9:4. The mass of the planet is 9/1 th of that of the Earth. If ‘R’ is the radius of the Earth, what is the radius of the planet ? (Take the planets to [...]
A spaceship orbits around a planet at a height of 20 km from its surface. Assuming that only gravitational field of the planet acts on the spaceship, what will be the number of complete revolutions made by the spaceship in 24 hours around the planet ? [Given : Mass of planet = 8×10^22 kg; Radius of planet = 2×10^6m, Gravitational constant G=6.67×10^−11 Nm^2/kg^2]
19
Sep
A spaceship orbits around a planet at a height of 20 km from its surface. Assuming that only gravitational field of the planet acts on the spaceship, what will be the number of complete revolutions made by the spaceship in 24 hours around the planet ? [Given : Mass of planet = 8×10^22 kg; Radius [...]
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A spaceship orbits around a planet at a height of 20 km from its surface. Assuming that only gravitational field of the planet acts on the spaceship ,
Gravitational constant G=6.67×10^−11 Nm^2/kg^2] ,
what will be the number of complete revolutions made by the spaceship in 24 hours around the planet ? [Given : Mass of planet = 8×10^22 kg; Radius of planet = 2×10^6m ,
The value of acceleration due to gravity at Earth’s surface is 9.8ms^−2 . The altitude above its surface at which the acceleration due to gravity decreases to 4.9ms ^−2 , is close to :(Radius of earth =6.4×10^6 m)
19
Sep
The value of acceleration due to gravity at Earth’s surface is 9.8ms^−2 . The altitude above its surface at which the acceleration due to gravity decreases to 4.9ms ^−2 , is close to :(Radius of earth =6.4×10^6 m) is close to :(Radius of earth =6.4×10^6 m) The value of acceleration due to gravity at Earth's [...]