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The activity of a sample of radioactive material is A1 at time t1 and A2 at time t2 (t2 > t1). Obtain an expression for its mean-life.
17
Oct
The activity of a sample of radioactive material is A1 at time t1 and A2 at time t2 (t2 > t1). Obtain an expression for its mean-life. The activity of a sample of radioactive material is A1 at time t1 and A2 at time t2 (t2 > t1). Obtain an expression for its mean-life. October [...]
Calculate the time taken to decay 100 percent of a radioactive sample in terms of (a) half-life T and (b) mean-life Tav.
17
Oct
Calculate the time taken to decay 100 percent of a radioactive sample in terms of (a) half-life T and (b) mean-life Tav. Calculate the time taken to decay 100 percent of a radioactive sample in terms fo (a) half-life T and (b) mean-life Tav. October 17, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma [...]
Two long parallel wires, AB and CD, carry equal currents in opposite directions. They lie in the x-y plane, parallel to the x-axis, and pass through the points (0,-a,0) and (0,a,0) respectively, Figure. The resultant magnetic field is:
17
Oct
Two long parallel wires, AB and CD, carry equal currents in opposite directions. They lie in the x-y plane, parallel to the x-axis, and pass through the points (0,-a,0) and (0,a,0) respectively, Figure. The resultant magnetic field is: 0) and (0 0) respectively A) AB and CD and pass through the points (0 carry equal [...]
Figure shows cross section of two large parallel metal sheets carrying electric currents along their surface. The current in each sheet is 10/πA/m along the width, Consider two points A and B, as shown in the figure with their positions.
17
Oct
Figure shows cross section of two large parallel metal sheets carrying electric currents along their surface. The current in each sheet is 10/πA/m along the width, Consider two points A and B, as shown in the figure with their positions. as shown in the figure with their positions. Consider two points A and B Figure [...]
A radioactive sample has mass m, decay constant lemda, and molecular weight M. If the Avogadro number is NA, then
17
Oct
A radioactive sample has mass m, decay constant lemda, and molecular weight M. If the Avogadro number is NA, then A radioactive sample has mass m and molecular weight M. If the Avogadro number is NA decay constant lemda then October 17, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,
Two circular coil of radii 5 cm and 10 cm carry equal currents of 2 A. The coils have 50 and 100 turns, respectively, and are placed in such a way that their planes as well as their centers coincide. Magnitude of magnetic field at the common centre of coils is
17
Oct
Two circular coil of radii 5 cm and 10 cm carry equal currents of 2 A. The coils have 50 and 100 turns, respectively, and are placed in such a way that their planes as well as their centers coincide. Magnitude of magnetic field at the common centre of coils is and are placed in [...]
The half-life of radon is 3.8 days. After how many days will only one-twentieth of radon sample be left over ?
17
Oct
The half-life of radon is 3.8 days. After how many days will only one-twentieth of radon sample be left over ? The half-life of radon is 3.8 days. After how many days will only one-twentieth of radon sample be left over ? October 17, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP [...]
3. The height of a cone is 15cm. If its volume is 1570 cm^3, find the diameter of its base. (Use π = 3.14)
17
Oct
3. The height of a cone is 15cm. If its volume is 1570 cm^3, find the diameter of its base. (Use π = 3.14) 3. The height of a cone is 15cm. If its volume is 1570 cm^3 find the diameter of its base. (Use π = 3.14) October 17, 2020 Category: Chapter 13 - [...]
2. Find the capacity in litres of a conical vessel with (ii) height 12 cm, slant height 12 cm
17
Oct
2. Find the capacity in litres of a conical vessel with (ii) height 12 cm, slant height 12 cm 2. Find the capacity in litres of a conical vessel with (ii) height 12 cm slant height 12 cm October 17, 2020 Category: Chapter 13 - Surface Areas and Volumes , Maths , NCERT Class 9 [...]
Find the half-life of 238U if 1 g of it emits 1.24 * 10^4 alpha particles per second. Avogadro’s number = 6.023 * 10^23.
17
Oct
Find the half-life of 238U if 1 g of it emits 1.24 * 10^4 alpha particles per second. Avogadro’s number = 6.023 * 10^23. Find the half-life of 238U if 1 g of it emits 1.24 * 10^4 alpha particles per second. Avogadro's number = 6.023 * 10^23. October 17, 2020 Category: Uncategorised (JEE Advanced [...]