then the ratio λ1/λ2 will be

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The potential energy of a particle of mass m is given by U(x) = {E000≤x1 λ1 and λ2 are the de-Broglie wavelength of the particle, when 0≤x≤1 and x>1 respectively. If the total energy of particle is 2E0 , then the ratio λ1/λ2 will be
13
Sep
The potential energy of a particle of mass m is given by U(x) = {E000≤x1 λ1 and λ2 are the de-Broglie wavelength of the particle, when 0≤x≤1 and x>1 respectively. If the total energy of particle is 2E0 , then the ratio λ1/λ2 will be The potential energy of a particle of mass m is [...]
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Tags: The potential energy of a particle of mass m is given by U(x) = {E000≤x1 λ1 and λ2 are the de-Broglie wavelength of the particle , then the ratio λ1/λ2 will be , when 0≤x≤1 and x>1 respectively. If the total energy of particle is 2E0 ,