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Two resistances R1 = 100 +- 3 ohm and R2 = 200 +- 4 ohm are connected in series. Find the equivalent resistance of the series combination.
14
Sep
Two resistances R1 = 100 +- 3 ohm and R2 = 200 +- 4 ohm are connected in series. Find the equivalent resistance of the series combination. Two resistances R1 = 100 +- 3 ohm and R2 = 200 +- 4 ohm are connected in series. Find the equivalent resistance of the series combination. September [...]
Infinite number of masses, each of 1kg, are placed along the x-axis at x=±1m, ±2m, ±4m, ±8m, ±16 m.. The gravitational of the resultant gravitational potential in term of gravitational constant G at the origin (x = 0) is
14
Sep
Infinite number of masses, each of 1kg, are placed along the x-axis at x=±1m, ±2m, ±4m, ±8m, ±16 m.. The gravitational of the resultant gravitational potential in term of gravitational constant G at the origin (x = 0) is ±16 m.. The gravitational of the resultant gravitational potential in term of gravitational constant G at [...]
The time period of a pendulum is given by T = 2 pie root L/g. The length of pendulum is 20 cm and is measured up to 1 mm accuracy. The time period is about 0.6 s. The time of 100 oscillations
14
Sep
The time period of a pendulum is given by T = 2 pie root L/g. The length of pendulum is 20 cm and is measured up to 1 mm accuracy. The time period is about 0.6 s. The time of 100 oscillations The time period of a pendulum is given by T = 2 pie [...]
Calculate the percentage error in specific resistance, p = pie r^2 R/l, where r = radius of wire = 0.26 +- 0.02 cm, l = length of wire = 156.0 +- 0.1 cm, and R = resistance
14
Sep
Calculate the percentage error in specific resistance, p = pie r^2 R/l, where r = radius of wire = 0.26 +- 0.02 cm, l = length of wire = 156.0 +- 0.1 cm, and R = resistance and R = resistance Calculate the percentage error in specific resistance l = length of wire = 156.0 [...]
The radius of a sphere is measured to be (2.1 +- 0.5) cm. Calculate its surface area with error limits.
14
Sep
The radius of a sphere is measured to be (2.1 +- 0.5) cm. Calculate its surface area with error limits. The radius of a sphere is measured to be (2.1 +- 0.5) cm. Calculate its surface area with error limits. September 14, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,
A body travels uniformly a distance of 13.8 +- 0.2) m in a time (4.0 +- 0.3)s. Calculate its velocity with error limits, what is the percentage error in velocity?
14
Sep
A body travels uniformly a distance of 13.8 +- 0.2) m in a time (4.0 +- 0.3)s. Calculate its velocity with error limits, what is the percentage error in velocity? A body travels uniformly a distance of 13.8 +- 0.2) m in a time (4.0 +- 0.3)s. Calculate its velocity with error limits what is [...]
Four particles each of mass M, are located at the vertices of a square with side L. The gravitational potential due to this at the centre of the square is
14
Sep
Four particles each of mass M, are located at the vertices of a square with side L. The gravitational potential due to this at the centre of the square is are located at the vertices of a square with side L. The gravitational potential due to this at the centre of the square is Four [...]
Two bodies of masses m and 4 m are placed at a distance r. The gravitational potential at a point on the line joining them where the gravitational field is zero is :
14
Sep
Two bodies of masses m and 4 m are placed at a distance r. The gravitational potential at a point on the line joining them where the gravitational field is zero is : Two bodies of masses m and 4 m are placed at a distance r. The gravitational potential at a point on the [...]
Suppose, the acceleration due to gravity at the Earth’s surface is 10ms^−2 and at the surface of Mars it is 4.0ms^−2. A 60 kg passenger goes from the Earth to the Mars in a spaceship moving with a constant velocity. Neglect all other objects in the sky. Which part of figure best represents the weight (net gravitational force) of the passenger as a function of time.
14
Sep
Suppose, the acceleration due to gravity at the Earth’s surface is 10ms^−2 and at the surface of Mars it is 4.0ms^−2. A 60 kg passenger goes from the Earth to the Mars in a spaceship moving with a constant velocity. Neglect all other objects in the sky. Which part of figure best represents the weight [...]
The radius of the earth is 6400 km and g = 10 ms^−2. In order that the body of 5 kg weighs zero at the equator, the angular speed of the earth is
14
Sep
The radius of the earth is 6400 km and g = 10 ms^−2. In order that the body of 5 kg weighs zero at the equator, the angular speed of the earth is the angular speed of the earth is The radius of the earth is 6400 km and g = 10 ms^−2. In order [...]