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A particle of mass M at rest decays into two masses m1 and m2 with non-zero velocities. The ratio lemda 1 / lemda 2 of de Broglie wavelengths of the particles is
14
Oct
A particle of mass M at rest decays into two masses m1 and m2 with non-zero velocities. The ratio lemda 1 / lemda 2 of de Broglie wavelengths of the particles is A particle of mass M at rest decays into two masses m1 and m2 with non-zero velocities. The ratio lemda 1 / lemda [...]
An electron is moving along the positive x-axis. You want to apply a magnetic field for a short time so that the electron may reverse its direction and move parallel to the negative x-axis. This can be done by applying the magnetic field along :
14
Oct
An electron is moving along the positive x-axis. You want to apply a magnetic field for a short time so that the electron may reverse its direction and move parallel to the negative x-axis. This can be done by applying the magnetic field along : The force F experienced by a particle of chrage q [...]
The de Broglie wavelength of neutrons in thermal equilibrium is (given mn = 1.6 * 10^-27 kg)
14
Oct
The de Broglie wavelength of neutrons in thermal equilibrium is (given mn = 1.6 * 10^-27 kg) The de Broglie wavelength of neutrons in thermal equilibrium is (given mn = 1.6 * 10^-27 kg) October 14, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,
A charged particle is fired at an anglle theta to a uniform magnetic field directed along the x axis . During its motion along a helical path, the partical will
14
Oct
A charged particle is fired at an anglle theta to a uniform magnetic field directed along the x axis . During its motion along a helical path, the partical will A charged particle is fired at an anglle theta to a uniform magnetic field directed along the x axis . During its motion along a [...]
When a metallic surface is illuminated by a light of frequency 8 * 10^14 Hz, photoelectron of maximum energy 0.5 eV is emitted. When the same surface is illuminated by light of frequency
14
Oct
When a metallic surface is illuminated by a light of frequency 8 * 10^14 Hz, photoelectron of maximum energy 0.5 eV is emitted. When the same surface is illuminated by light of frequency photoelectron of maximum energy 0.5 eV is emitted. When the same surface is illuminated by light of frequency When a metallic surface [...]
In previous problem, if the pitch of the helical path is equal to the maximum distance of the particle from the x – axis , then which of the following are not correct ?
14
Oct
In previous problem, if the pitch of the helical path is equal to the maximum distance of the particle from the x – axis , then which of the following are not correct ? if the pitch of the helical path is equal to the maximum distance of the particle from the x - axis [...]
Which of the following statements is correct ? (1) If a moving charged particle enters into a region of magnetic field from outside, it does not complete a circular path.
14
Oct
Which of the following statements is correct ? (1) If a moving charged particle enters into a region of magnetic field from outside, it does not complete a circular path. it does not complete a circular path. Which of the following statements is correct ? (1) If a moving charged particle enters into a region [...]
If lemda0 stands for mid-wavelength in the visible region, the de Broglie wavelength for 100 V electrons is nearest to
14
Oct
If lemda0 stands for mid-wavelength in the visible region, the de Broglie wavelength for 100 V electrons is nearest to If lemda0 stands for mid-wavelength in the visible region the de Broglie wavelength for 100 V electrons is nearest to October 14, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,
The KE of the photoelectrons is E when the incident wavelength is lemda/2. The KE becomes 2E when the incident wavelength is lemda/3. The work function of the metal is
14
Oct
The KE of the photoelectrons is E when the incident wavelength is lemda/2. The KE becomes 2E when the incident wavelength is lemda/3. The work function of the metal is The KE of the photoelectrons is E when the incident wavelength is lemda/2. The KE becomes 2E when the incident wavelength is lemda/3. The work [...]
The kinetic energy of an electron is E when the incident wavelength is lemda. To increase the KE of the electron to 2E, the incident wavelength must be
14
Oct
The kinetic energy of an electron is E when the incident wavelength is lemda. To increase the KE of the electron to 2E, the incident wavelength must be the incident wavelength must be The kinetic energy of an electron is E when the incident wavelength is lemda. To increase the KE of the electron to [...]