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If the first excitation potential of a hydrogen-like atom is V electron volt, then the ionization energy of this atom will be
15
Oct
If the first excitation potential of a hydrogen-like atom is V electron volt, then the ionization energy of this atom will be If the first excitation potential of a hydrogen-like atom is V electron volt then the ionization energy of this atom will be October 15, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma [...]
Example 5 : If a transversal intersects two lines such that the bisectors of a pair of corresponding angles are parallel, then prove that the two lines are parallel.
15
Oct
Example 5 : If a transversal intersects two lines such that the bisectors of a pair of corresponding angles are parallel, then prove that the two lines are parallel. Example 5 : If a transversal intersects two lines such that the bisectors of a pair of corresponding angles are parallel then prove that the two [...]
Example 4 : In fig .6.24,if PQ//RS, angle MXQ =135 and angle MYR =40 , find angle XMY.
15
Oct
Example 4 : In fig .6.24,if PQ//RS, angle MXQ =135 and angle MYR =40 , find angle XMY. angle MXQ =135 and angle MYR =40 Example 4 : In fig .6.24 find angle XMY. if PQ || RS October 15, 2020 Category: Chapter 6 - Lines and Angles , Maths , NCERT Class 9 ,
In hydrogen spectrum, the shortest wavelength in Balmer series is the lemda. The shortest wavelength in the Brackett series will be
15
Oct
In hydrogen spectrum, the shortest wavelength in Balmer series is the lemda. The shortest wavelength in the Brackett series will be In hydrogen spectrum the shortest wavelength in Balmer series is the lemda. The shortest wavelength in the Brackett series will be October 15, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP [...]
Example 3 : In figure, OP, OQ, OR and OS are four rays. Prove that ∠ POQ + ∠ QOR + ∠ SOR + ∠ POS = 360°.
15
Oct
Example 3 : In figure, OP, OQ, OR and OS are four rays. Prove that ∠ POQ + ∠ QOR + ∠ SOR + ∠ POS = 360°. Example 3 : In figure OP OQ OR and OS are four rays. Prove that ∠ POQ + ∠ QOR + ∠ SOR + ∠ POS = [...]
If an electron in n=3 orbit of hydrogen atom jumps down to n = 2 orbit, the amount of energy released and the wavelength of radiation emitted are
15
Oct
If an electron in n=3 orbit of hydrogen atom jumps down to n = 2 orbit, the amount of energy released and the wavelength of radiation emitted are If an electron in n=3 orbit of hydrogen atom jumps down to n = 2 orbit the amount of energy released and the wavelength of radiation emitted [...]
In Fig.6.10,ray OS stands on a line POQ . Ray OR and ray OT are angle bisector of angle POS and angle SOQ, respectively . If angle POS=x, find angle ROT.
15
Oct
In Fig.6.10,ray OS stands on a line POQ . Ray OR and ray OT are angle bisector of angle POS and angle SOQ, respectively . If angle POS=x, find angle ROT. find angle ROT. In Fig.6.10 ray OS stands on a line POQ . Ray OR and ray OT are angle bisector of angle POS [...]
Example 1 In Fig, lines PQ and RS intersect each other at point O. If ∠ POR : ∠ ROQ = 5 : 7, find all the angles.
15
Oct
Example 1 In Fig, lines PQ and RS intersect each other at point O. If ∠ POR : ∠ ROQ = 5 : 7, find all the angles. Example 1 In Fig find all the angles. lines PQ and RS intersect each other at point O. If ∠ POR : ∠ ROQ = 5 : [...]
The ratio (in SI units) of magnetic dipole moment to that of the angular momentum of an electron of mass m kg and charge e coulomb in Bohr’s orbit of hydrogen atom is
15
Oct
The ratio (in SI units) of magnetic dipole moment to that of the angular momentum of an electron of mass m kg and charge e coulomb in Bohr’s orbit of hydrogen atom is The ratio (in SI units) of magnetic dipole moment to that of the angular momentum of an electron of mass m kg [...]
6. In Fig. 6.44, the side QR of ΔPQR is produced to a point S. If the bisectors of angle PQR and angle PRS meet at point T, then prove that angle QTR = ½ angle QPR.
15
Oct
6. In Fig. 6.44, the side QR of ΔPQR is produced to a point S. If the bisectors of angle PQR and angle PRS meet at point T, then prove that angle QTR = ½ angle QPR. 6. In Fig. 6.44 the side QR of ΔPQR is produced to a point S. If the bisectors [...]