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The elements which are radioactive and have been named after the names of planets are (a) Hg (b) Np (c) Pu (d) Ra
11
Nov
The elements which are radioactive and have been named after the names of planets are (a) Hg (b) Np (c) Pu (d) Ra The elements which are radioactive and have been named after the names of planets are (a) Hg (b) Np (c) Pu (d) Ra November 11, 2020 Category: Uncategorised (JEE Advanced Physics by [...]
Select equations having endothermic step (a) S-(g) to S 2- (g) (b) Na +(g) + Cl- (g) to NaCl (s) (c) N (g) to N- (g)
11
Nov
Select equations having endothermic step (a) S-(g) to S 2- (g) (b) Na +(g) + Cl- (g) to NaCl (s) (c) N (g) to N- (g) Select equations having endothermic step (a) S-(g) to S 2- (g) (b) Na +(g) + Cl- (g) to NaCl (s) (c) N (g) to N- (g) November 11, 2020 [...]
Which of the following pair of ions have the same number of unpaired electrons (a) Mn 2+ and Fe 2+ (b) Mn 2+ and Fe 3+ (c) Tu 2+ and Ni 2+
11
Nov
Which of the following pair of ions have the same number of unpaired electrons (a) Mn 2+ and Fe 2+ (b) Mn 2+ and Fe 3+ (c) Tu 2+ and Ni 2+ Which of the following pair of ions have the same number of unpaired electrons (a) Mn 2+ and Fe 2+ (b) Mn 2+ [...]
To observe diffraction, the size of the obstacle
11
Nov
To observe diffraction, the size of the obstacle the size of the obstacle To observe diffraction November 11, 2020 Category: Chapter 10 - Wave Optics , MTG NEET Physics , Part 2 ,
What will be the angle of diffraction for the first order maximum due to Fraunhofer diffraction by a single slit of width 0.4 mm, using light of wavelength 4000 A ?
11
Nov
What will be the angle of diffraction for the first order maximum due to Fraunhofer diffraction by a single slit of width 0.4 mm, using light of wavelength 4000 A ? using light of wavelength 4000 A ? What will be the angle of diffraction for the first order maximum due to Fraunhofer diffraction by [...]
In Fraunhofer diffraction pattern, slit width is 0.2mm and screen is at 2 m away from the lens. If wavelength of light used is 5000Å, then the distance between the first minimum on either side of the central maximum is (θ is small and measured in radian)
11
Nov
In Fraunhofer diffraction pattern, slit width is 0.2mm and screen is at 2 m away from the lens. If wavelength of light used is 5000Å, then the distance between the first minimum on either side of the central maximum is (θ is small and measured in radian) In Fraunhofer diffraction pattern slit width is 0.2mm [...]
If Aufbau principle and Hund’s rule were not followed (a) Ca would have been d-block element with zero dipole moment (b) Zn would have been s-block element
11
Nov
If Aufbau principle and Hund’s rule were not followed (a) Ca would have been d-block element with zero dipole moment (b) Zn would have been s-block element If Aufbau principle and Hund's rule were not followed (a) Ca would have been d-block element with zero dipole moment (b) Zn would have been s-block element November [...]
In the circuit shown in figure, switch S is closed at time t = 0 . (a) what is the current I0 leaving the battery at t = 0 , immediately after the switch is closed ?
11
Nov
In the circuit shown in figure, switch S is closed at time t = 0 . (a) what is the current I0 leaving the battery at t = 0 , immediately after the switch is closed ? immediately after the switch is closed ? In the circuit shown in Figure switch S is closed at [...]
For what distance is ray optics a good approximation when the aperture is 4 mm and the wavelength of light is 400 nm?
11
Nov
For what distance is ray optics a good approximation when the aperture is 4 mm and the wavelength of light is 400 nm? For what distance is ray optics a good approximation when the aperture is 4 mm and the wavelength of light is 400 nm? November 11, 2020 Category: Chapter 10 - Wave Optics [...]
The equilibrium constant kc for the reaction SO2(g) + NO2(g) ⇌ SO3(g) + NO(g) is 16. If 1 mole of each of all the four gases is taken in 1 dm^3 vessel, the equilibrium concentration of no would be:
11
Nov
The equilibrium constant kc for the reaction SO2(g) + NO2(g) ⇌ SO3(g) + NO(g) is 16. If 1 mole of each of all the four gases is taken in 1 dm^3 vessel, the equilibrium concentration of no would be: the equilibrium concentration of no would be: The equilibrium constant kc for the reaction SO2(g) + [...]