Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions)
The oxidation number of nickel in K4 [Ni (CN )4] is (a) -2 (b) -1 (c) +2 (d) 0
24
Nov
The oxidation number of nickel in K4 [Ni (CN )4] is (a) -2 (b) -1 (c) +2 (d) 0 The oxidation number of nickel in K4 [Ni (CN )4] is (a) -2 (b) -1 (c) +2 (d) 0 November 24, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,
The oxidation states of S atoms in S4O6^2-from left to right respectively are
24
Nov
The oxidation states of S atoms in S4O6^2-from left to right respectively are The oxidation states of S atoms in S4O6^2-from left to right respectively are November 24, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,
Which of the following chloride is water insoluble (a) HCl (b) AgCl (c) Both (a) and (b) (d) None of these
24
Nov
Which of the following chloride is water insoluble (a) HCl (b) AgCl (c) Both (a) and (b) (d) None of these Which of the following chloride is water insoluble (a) HCl (b) AgCl (c) Both (a) and (b) (d) None of these November 24, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP [...]
Bleaching powder is correctly represented as (a) CaOCl2 (b) CaO (c) CaO(Cl) (d) CaCl(OCl)
24
Nov
Bleaching powder is correctly represented as (a) CaOCl2 (b) CaO (c) CaO(Cl) (d) CaCl(OCl) Bleaching powder is correctly represented as (a) CaOCl2 (b) CaO (c) CaO(Cl) (d) CaCl(OCl) November 24, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,
White enamel of our teeth is (a) Ca3(PO4)2 (b) CaF2 (c) CaCl2 (d) CaBr2
24
Nov
White enamel of our teeth is (a) Ca3(PO4)2 (b) CaF2 (c) CaCl2 (d) CaBr2 White enamel of our teeth is (a) Ca3(PO4)2 (b) CaF2 (c) CaCl2 (d) CaBr2 November 24, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,
Bleaching action of chlorine is due to (a) Oxidation (b) Reduction (c) Hydrolysis (d) Its acidic nature
24
Nov
Bleaching action of chlorine is due to (a) Oxidation (b) Reduction (c) Hydrolysis (d) Its acidic nature Bleaching action of chlorine is due to (a) Oxidation (b) Reduction (c) Hydrolysis (d) Its acidic nature November 24, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,
The element which never acts as reducing agent in a chemical reaction is (a) O (b) Li (c) F (d) C
24
Nov
The element which never acts as reducing agent in a chemical reaction is (a) O (b) Li (c) F (d) C The element which never acts as reducing agent in a chemical reaction is (a) O (b) Li (c) F (d) C November 24, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP [...]
When a manganous salt is fused with a mixture of KNO3 and solid NaOH the oxidation number of Mn changes from +2 to
24
Nov
When a manganous salt is fused with a mixture of KNO3 and solid NaOH the oxidation number of Mn changes from +2 to When a manganous salt is fused with a mixture of KNO3 and solid NaOH the oxidation number of Mn changes from +2 to November 24, 2020 Category: Uncategorised (JEE Advanced Physics by [...]
Consider the following treaction 6NaOH +3Cl2 gives 5NaCL +A +3H2O what is the oxidation number of chlorine in A
24
Nov
Consider the following treaction 6NaOH +3Cl2 gives 5NaCL +A +3H2O what is the oxidation number of chlorine in A Consider the following treaction 6NaOH +3Cl2 gives 5NaCL +A +3H2O what is the oxidation number of chlorine in A November 24, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,
HI cannot be prepared by the action of conc. H2SO4 on KI because (a) HI is stronger than H2SO4 (b) HI is more volatile than H2SO4
24
Nov
HI cannot be prepared by the action of conc. H2SO4 on KI because (a) HI is stronger than H2SO4 (b) HI is more volatile than H2SO4 HI cannot be prepared by the action of conc. H2SO4 on KI because (a) HI is stronger than H2SO4 (b) HI is more volatile than H2SO4 November 24, 2020 [...]