Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions)
A cell can be balanced against 110 cm and 100 cm of potentiometer wire, respectively with and without being short circuited through a resistance of 10 Ω Its internal resistance is
07
Dec
A cell can be balanced against 110 cm and 100 cm of potentiometer wire, respectively with and without being short circuited through a resistance of 10 Ω Its internal resistance is A cell can be balanced against 110 cm and 100 cm of potentiometer wire respectively with and without being short circuited through a resistance [...]
A potentiometer circuit is setup as shown. The potential gradient across the potentiometer wire is k volt/cm and the ammeter present in the circuit reads. 1.0A When two-way key is switched off. The balance point, when the key between the terminals (i) 1 and 2 (ii) 1 and 3, is plugged in, are found to be at lengths l2cm and l2cm respectively. The magnitudes, of the resistors R and X, in ohm, are then, equal, respectively, to
07
Dec
A potentiometer circuit is setup as shown. The potential gradient across the potentiometer wire is k volt/cm and the ammeter present in the circuit reads. 1.0A When two-way key is switched off. The balance point, when the key between the terminals (i) 1 and 2 (ii) 1 and 3, is plugged in, are found to [...]
A potentiometer circuit has been set up for finding the internal resistance of a given cell. The main battery, used across the potentiometer wire, has an emf of 2.0 V and a negligible internal resistance. The potentiometer wire itself is 4 m long. When the resistance, R, connected across the given cell, has values of (i) infinity (ii) 9.5Ω The ‘balancing lengths, on the potentiometer wire are found to be 3m and 2.85 m, respectively. The value of internal resistance of the cell is
07
Dec
A potentiometer circuit has been set up for finding the internal resistance of a given cell. The main battery, used across the potentiometer wire, has an emf of 2.0 V and a negligible internal resistance. The potentiometer wire itself is 4 m long. When the resistance, R, connected across the given cell, has values of [...]
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A potentiometer circuit has been set up for finding the internal resistance of a given cell. The main battery ,
connected across the given cell ,
has an emf of 2.0 V and a negligible internal resistance. The potentiometer wire itself is 4 m long. When the resistance ,
has values of (i) infinity (ii) 9.5Ω The 'balancing lengths ,
on the potentiometer wire are found to be 3m and 2.85 m ,
R ,
respectively. The value of internal resistance of the cell is ,
used across the potentiometer wire ,
A potentiometer wire of Length L and a resistance r are connected in series with a battery of e.m.f. E0 and a resistance r1. An unknown e.m.f. E is balanced at a length l of the potentiometer wire. The e.m.f. E will be given by
07
Dec
A potentiometer wire of Length L and a resistance r are connected in series with a battery of e.m.f. E0 and a resistance r1. An unknown e.m.f. E is balanced at a length l of the potentiometer wire. The e.m.f. E will be given by Faraday's laws are consequence of conservation of December 7, 2020 [...]
The resistance in the two arms of the meter bridge are 5Ω and RΩ, respectively. When the resistance R is shunted with an equal resistance, the new balance point is at 1.6l1. The resistance ‘R’ is
07
Dec
The resistance in the two arms of the meter bridge are 5Ω and RΩ, respectively. When the resistance R is shunted with an equal resistance, the new balance point is at 1.6l1. The resistance ‘R’ is respectively. When the resistance R is shunted with an equal resistance the new balance point is at 1.6l1. The [...]
A potentiometer wire has length 4m and resistance 8Ω. The resistance that must be connected in series with the wire and an accumulator of e.m.f. 2V, so as the get a potential gradient 1mV per cm` on the wire is
07
Dec
A potentiometer wire has length 4m and resistance 8Ω. The resistance that must be connected in series with the wire and an accumulator of e.m.f. 2V, so as the get a potential gradient 1mV per cm` on the wire is A potentiometer wire has length 4m and resistance 8Ω. The resistance that must be connected [...]
The metre bridge shown is in balance position with P/Q = l1/l2 . If we now interchange the positions of galvanometer and cell, will the bridge work ? If yes, that will be balanced condition ?
07
Dec
The metre bridge shown is in balance position with P/Q = l1/l2 . If we now interchange the positions of galvanometer and cell, will the bridge work ? If yes, that will be balanced condition ? that will be balanced condition ? The metre bridge shown is in balance position with P/Q = l1/l2 . [...]
In 1 gram of a metal oxide, metal precipitated is 0.68 gram. What is the equivalent weight of metal
07
Dec
In 1 gram of a metal oxide, metal precipitated is 0.68 gram. What is the equivalent weight of metal In 1 gram of a metal oxide metal precipitated is 0.68 gram. What is the equivalent weight of metal December 7, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,
Metallic tin in the presence of HCl is oxidised by K2Cr2O7 to stannic chloride. What volume of decinormal dichromate solution would be reduced by 1 g of tin
07
Dec
Metallic tin in the presence of HCl is oxidised by K2Cr2O7 to stannic chloride. What volume of decinormal dichromate solution would be reduced by 1 g of tin Metallic tin in the presence of HCl is oxidised by K2Cr2O7 to stannic chloride. What volume of decinormal dichromate solution would be reduced by 1 g of [...]
25 ml of a solution of Na2CO3 having a specific gravity of 1.25 required 32.9 ml of a solution of HCl containing 109.5 grams of the acid per litre for complete neutralization. Calculate the volume of
07
Dec
25 ml of a solution of Na2CO3 having a specific gravity of 1.25 required 32.9 ml of a solution of HCl containing 109.5 grams of the acid per litre for complete neutralization. Calculate the volume of 25 ml of a solution of Na2CO3 having a specific gravity of 1.25 required 32.9 ml of a solution [...]