△ODC∼△OBA

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In figure, △ODC∼△OBA, ∠BOC = 125 degree and ∠CDO=70 degree. Find ∠DOC, ∠DCO and ∠OAB.
04
Oct
In figure, △ODC∼△OBA, ∠BOC = 125 degree and ∠CDO=70 degree. Find ∠DOC, ∠DCO and ∠OAB. ∠BOC = 125 degree and ∠CDO=70 degree. Find ∠DOC ∠DCO and ∠OAB. △ODC∼△OBA In figure October 4, 2020 Category: Chapter 6 - Triangles , Maths , NCERT Class 10 ,
Posted in: Chapter 6 - Triangles , Maths , NCERT Class 10 ,
Tags: ∠BOC = 125 degree and ∠CDO=70 degree. Find ∠DOC , ∠DCO and ∠OAB. , △ODC∼△OBA , In figure ,
In figure, △ODC∼△OBA, ∠BOC = 125 degree and ∠CDO=70 degree. Find ∠DOC, ∠DCO and ∠OAB.
04
Oct
In figure, △ODC∼△OBA, ∠BOC = 125 degree and ∠CDO=70 degree. Find ∠DOC, ∠DCO and ∠OAB. ∠BOC = 125 degree and ∠CDO=70 degree. Find ∠DOC ∠DCO and ∠OAB. △ODC∼△OBA In figure October 4, 2020 Category: Chapter 6 - Triangles , Maths , NCERT Class 10 ,
Posted in: Chapter 6 - Triangles , Maths , NCERT Class 10 ,
Tags: ∠BOC = 125 degree and ∠CDO=70 degree. Find ∠DOC , ∠DCO and ∠OAB. , △ODC∼△OBA , In figure ,