y2 = 5[sin3πt + 3–√cos3πt] Then what is the ratio of their amplitudes

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The equation of displacement of two waves are given as y1=10sin(3πt + π/3),y2 = 5[sin3πt + 3–√cos3πt] Then what is the ratio of their amplitudes
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The equation of displacement of two waves are given as y1=10sin(3πt + π/3),y2 = 5[sin3πt + 3–√cos3πt] Then what is the ratio of their amplitudes The equation of displacement of two waves are given as y1=10sin(3πt + π/3) y2 = 5[sin3πt + 3–√cos3πt] Then what is the ratio of their amplitudes October 29, 2020 Category: [...]
Posted in: Cengage JEE Mains Physics by B.M Sharma , Chapter 16 - Waves and Acoustics ,
Tags: The equation of displacement of two waves are given as y1=10sin(3πt + π/3) , y2 = 5[sin3πt + 3–√cos3πt] Then what is the ratio of their amplitudes ,