…x=∞. Here x0 is a positive constant. Take the electric potential at a point due to a charge Q at a distance r from it to be Q/(4πε0r).Then

Sahay Sir > Question Answers > …x=∞. Here x0 is a positive constant. Take the electric potential at a point due to a charge Q at a distance r from it to be Q/(4πε0r).Then
A charge +q is fixed at each of the points x=x0, x=3×0, x=5×0,…x=∞ on the x axis, and a charge −q is fixed at each of the points x=2×0, x=4×0, x=6×0, …x=∞. Here x0 is a positive constant. Take the electric potential at a point due to a charge Q at a distance r from it to be Q/(4πε0r).Then, the potential at the origin due to the above system of charges is
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Dec
A charge +q is fixed at each of the points x=x0, x=3×0, x=5×0,…x=∞ on the x axis, and a charge −q is fixed at each of the points x=2×0, x=4×0, x=6×0, …x=∞. Here x0 is a positive constant. Take the electric potential at a point due to a charge Q at a distance r from [...]
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Tags: …x=∞ on the x axis , …x=∞. Here x0 is a positive constant. Take the electric potential at a point due to a charge Q at a distance r from it to be Q/(4πε0r).Then , A charge + q is fixed at each of the points x=x0 , and a charge −q is fixed at each of the points x=2x0 , the potential at the origin due to the above system of charges is , x=3x0 , x=4x0 , x=5x0 , x=6x0... ,