where alpha is a positive constant. At the start v=v0. The distance traveled by particle before it stops will be

Sahay Sir > Question Answers > where alpha is a positive constant. At the start v=v0. The distance traveled by particle before it stops will be
A point moves linearly with deceleration which is given by dv/dt = −αv√, where alpha is a positive constant. At the start v=v0. The distance traveled by particle before it stops will be
20
Oct
A point moves linearly with deceleration which is given by dv/dt = −αv√, where alpha is a positive constant. At the start v=v0. The distance traveled by particle before it stops will be A point moves linearly with deceleration which is given by dv/dt = −αv√ where alpha is a positive constant. At the start [...]
Posted in: Cengage NEET by C.P Singh , Chapter 2 - Motion in a Straight Line , Part 1 ,
Tags: A point moves linearly with deceleration which is given by dv/dt = −αv√ , where alpha is a positive constant. At the start v=v0. The distance traveled by particle before it stops will be ,