What is the concentration of CH3COOH(aq.) in a solution prepared by dissolving 0.01 mole of NH+4CH3COO− in 1 L H2O? [Ka(CH3COOH)=1.8×10^−5)

Sahay Sir > Question Answers > What is the concentration of CH3COOH(aq.) in a solution prepared by dissolving 0.01 mole of NH+4CH3COO− in 1 L H2O? [Ka(CH3COOH)=1.8×10^−5)
What is the concentration of CH3COOH(aq.) in a solution prepared by dissolving 0.01 mole of NH+4CH3COO− in 1 L H2O? [Ka(CH3COOH)=1.8×10^−5),Kb(NH4OH)=1.8×10^−5]
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What is the concentration of CH3COOH(aq.) in a solution prepared by dissolving 0.01 mole of NH+4CH3COO− in 1 L H2O? [Ka(CH3COOH)=1.8×10^−5),Kb(NH4OH)=1.8×10^−5] Kb(NH4OH)=1.8×10^−5] What is the concentration of CH3COOH(aq.) in a solution prepared by dissolving 0.01 mole of NH+4CH3COO− in 1 L H2O? [Ka(CH3COOH)=1.8×10^−5) November 18, 2020 Category: Chapter 6 - Ionic Equilibrium (Level 1 and [...]
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Tags: Kb(NH4OH)=1.8×10^−5] , What is the concentration of CH3COOH(aq.) in a solution prepared by dissolving 0.01 mole of NH+4CH3COO− in 1 L H2O? [Ka(CH3COOH)=1.8×10^−5) ,