vibrate according to equation Y1 = 0.03 sin pie t and Y2 = 0.02 sin pie t where y1

Sahay Sir > Question Answers > vibrate according to equation Y1 = 0.03 sin pie t and Y2 = 0.02 sin pie t where y1
Two sound sources S1 and S2 separated by 2.0 m, vibrate according to equation Y1 = 0.03 sin pie t and Y2 = 0.02 sin pie t where y1, y2 and t are in SI units. They send out waves of velocity 1.5 m/s. Calculate the amplitude of the resultant motion of the particle
06
Sep
Two sound sources S1 and S2 separated by 2.0 m, vibrate according to equation Y1 = 0.03 sin pie t and Y2 = 0.02 sin pie t where y1, y2 and t are in SI units. They send out waves of velocity 1.5 m/s. Calculate the amplitude of the resultant motion of the particle Two [...]
Posted in: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,
Tags: Two sound sources S1 and S2 separated by 2.0 m , vibrate according to equation Y1 = 0.03 sin pie t and Y2 = 0.02 sin pie t where y1 , y2 and t are in SI units. They send out waves of velocity 1.5 m/s. Calculate the amplitude of the resultant motion of the particle ,