using the identity a^2 – 2ab + b^2 = (a – b)^2. (xi) a^2y^3 – 2aby^2 + b^2y

Sahay Sir > Question Answers > using the identity a^2 – 2ab + b^2 = (a – b)^2. (xi) a^2y^3 – 2aby^2 + b^2y
90. Factorise the following, using the identity a^2 – 2ab + b^2 = (a – b)^2. (xi) a^2y^3 – 2aby^2 + b^2y
27
Jul
90. Factorise the following, using the identity a^2 – 2ab + b^2 = (a – b)^2. (xi) a^2y^3 – 2aby^2 + b^2y 90. Factorise the following using the identity a^2 – 2ab + b^2 = (a – b)^2. (xi) a^2y^3 – 2aby^2 + b^2y July 27, 2021 Category: Chapter 14 - Factorisation , Chapter 9 [...]
Posted in: Chapter 14 - Factorisation , Chapter 9 - Algebraic Expressions and Identities , Maths , NCERT Class 8 ,
Tags: 90. Factorise the following , using the identity a^2 – 2ab + b^2 = (a – b)^2. (xi) a^2y^3 – 2aby^2 + b^2y ,