using the identity a^2 + 2ab + b^2 = (a + b)^2 (v) 4x^2 + 4x + 1

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89. Factorise the following, using the identity a^2 + 2ab + b^2 = (a + b)^2 (v) 4x^2 + 4x + 1
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89. Factorise the following, using the identity a^2 + 2ab + b^2 = (a + b)^2 (v) 4x^2 + 4x + 1 89. Factorise the following using the identity a^2 + 2ab + b^2 = (a + b)^2 (v) 4x^2 + 4x + 1 July 27, 2021 Category: Chapter 14 - Factorisation , Chapter 9 [...]
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Tags: 89. Factorise the following , using the identity a^2 + 2ab + b^2 = (a + b)^2 (v) 4x^2 + 4x + 1 ,