Two waves y1 = 2sinωt and y2 = 4sin(ωt+δ) superimpose. The ratio of the maximum to the minimum intensity of the resultant wave is :-duplicate-5

Sahay Sir > Question Answers > Two waves y1 = 2sinωt and y2 = 4sin(ωt+δ) superimpose. The ratio of the maximum to the minimum intensity of the resultant wave is :-duplicate-5

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Two waves y1 = 2sinωt and y2 = 4sin(ωt+δ) superimpose. The ratio of the maximum to the minimum intensity of the resultant wave is :-duplicate-5 Two waves y1 = 2sinωt and y2 = 4sin(ωt+δ) superimpose. The ratio of the maximum to the minimum intensity of the resultant wave is :-duplicate-5 November 11, 2020 [...]

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Two waves y1 ​= 2sinωt and y2 ​ = 4sin(ωt+δ) superimpose. The ratio of the maximum to the minimum intensity of the resultant wave is :-duplicate-5

Two waves y1 = 2sinωt and y2 = 4sin(ωt+δ) superimpose. The ratio of the maximum to the minimum intensity of the resultant wave is :-duplicate-5