Two radioactive materials A and B decay constant 3 lemda and 2 lemda respectively. At t = 0

Sahay Sir > Question Answers > Two radioactive materials A and B decay constant 3 lemda and 2 lemda respectively. At t = 0
Nuclei A and B convert into a stable nucleus C. Nucleus A is converted into C by emitting 2 alpha particles and 3 beta particles. Nucleus B is converted into C by emitting one alpha particle and 5 beta particles.
20
Oct
Nuclei A and B convert into a stable nucleus C. Nucleus A is converted into C by emitting 2 alpha particles and 3 beta particles. Nucleus B is converted into C by emitting one alpha particle and 5 beta particles. the numbers of nuclei of A and B are 4 N0 and 2N0 respectively then [...]
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Two radioactive materials A and B decay constant 3 lemda and 2 lemda respectively. At t = 0, the numbers of nuclei of A and B are 4 N0 and 2N0 respectively, then
20
Oct
Two radioactive materials A and B decay constant 3 lemda and 2 lemda respectively. At t = 0, the numbers of nuclei of A and B are 4 N0 and 2N0 respectively, then the numbers of nuclei of A and B are 4 N0 and 2N0 respectively then Two radioactive materials A and B decay [...]
Posted in: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,
Tags: the numbers of nuclei of A and B are 4 N0 and 2N0 respectively , then , Two radioactive materials A and B decay constant 3 lemda and 2 lemda respectively. At t = 0 ,