two chords AB and CD of a circle intersect each other at the point P (when produced) outside the circle. prove that (1) triangle PAC ~ triangle PDB

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In fig. 6.62, two chords AB and CD of a circle intersect each other at the point P (when produced) outside the circle. prove that (1) triangle PAC ~ triangle PDB ,(2) PA.PB = PC.PD
05
Oct
In fig. 6.62, two chords AB and CD of a circle intersect each other at the point P (when produced) outside the circle. prove that (1) triangle PAC ~ triangle PDB ,(2) PA.PB = PC.PD (2) PA.PB = PC.PD In fig. 6.62 two chords AB and CD of a circle intersect each other at the [...]
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Tags: (2) PA.PB = PC.PD , In fig. 6.62 , two chords AB and CD of a circle intersect each other at the point P (when produced) outside the circle. prove that (1) triangle PAC ~ triangle PDB ,