to get its inverted real image at A’ itself. The value of μ1 will be
A thin convex lens L (refractive index = 1.5) is placed on a plane mirror M. When a pin is placed at A, such that OA = 18 cm, its real inverted image is formed at A itself, as shown in figure. When a liquid of refractive index μ1 is put between the lens and the mirror, The pin has to be moved to A’, such that OA’ = 27 cm, to get its inverted real image at A’ itself. The value of μ1 will be
18
Nov
A thin convex lens L (refractive index = 1.5) is placed on a plane mirror M. When a pin is placed at A, such that OA = 18 cm, its real inverted image is formed at A itself, as shown in figure. When a liquid of refractive index μ1 is put between the lens and [...]
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A thin convex lens L (refractive index = 1.5) is placed on a plane mirror M. When a pin is placed at A ,
as shown in figure. When a liquid of refractive index μ1 is put between the lens and the mirror ,
its real inverted image is formed at A itself ,
such that OA = 18 cm ,
such that OA' = 27 cm ,
The pin has to be moved to A' ,
to get its inverted real image at A' itself. The value of μ1 will be ,