to come to rest
An object, moving with a speed of 6.25 m/s, is decelerated at a rate given by: dt/dv = − 2.5v where v is the instantaneous speed. The time taken by the object, to come to rest, would be:
10
Sep
An object, moving with a speed of 6.25 m/s, is decelerated at a rate given by: dt/dv = − 2.5v where v is the instantaneous speed. The time taken by the object, to come to rest, would be: An object is decelerated at a rate given by: dt/dv = − 2.5v where v is the [...]