Three identical cells
Three identical cells, each having an e.m.f. of 1.5 V and a constant internal resistance of 2.0Ω, are connected in series with a 4.0 Ω resistance R, first as in circuit (1), and second as in circuit (ii). what is the ratio Power in R in circuit (ii)/Power in R in circuit (i) ?
06
Dec
Three identical cells, each having an e.m.f. of 1.5 V and a constant internal resistance of 2.0Ω, are connected in series with a 4.0 Ω resistance R, first as in circuit (1), and second as in circuit (ii). what is the ratio Power in R in circuit (ii)/Power in R in circuit (i) ? [...]
A wire of length L and 3 identical cells of negligible internal resistance are connected in series. Due to the current, the temperature of the wire is raised by ΔT in a time t. A number N of similar cells is now connected in series with a wire of the same material and cross-section but of length 2L. The temperature of the wire is raised by the same amount ΔT in the same time t. the value of N is
17
Nov
A wire of length L and 3 identical cells of negligible internal resistance are connected in series. Due to the current, the temperature of the wire is raised by ΔT in a time t. A number N of similar cells is now connected in series with a wire of the same material and cross-section but [...]
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A wire of length L and 3 identical cells of negligible internal resistance are connected in series. Due to the current ,
and second as in circuit (ii) . Then ( power in R in circuit (i))/( Power in R in circuit (ii)) = ,
are connected in series with a 4.0ωresis→rR ,
each having an emf1.5V and a constant internal resistance 2.0ω ,
first as in circuit (i) ,
Three identical cells ,
Three identical cells , each having an emf1.5V and a constant internal resistance 2.0ω, are connected in series with a 4.0ωresis→rR, first as in circuit (i) , and second as in circuit (ii) . Then ( power in R in circuit (i))/( Power in R in circuit (ii)) =
15
Nov
Three identical cells , each having an emf1.5V and a constant internal resistance 2.0ω, are connected in series with a 4.0ωresis→rR, first as in circuit (i) , and second as in circuit (ii) . Then ( power in R in circuit (i))/( Power in R in circuit (ii)) = and second as in circuit (ii) [...]