then the number of electrons emitted per second per unit area from the surface will be : [Planck constant h=6.64×10^−34 Js; Velocity of light =3×10^8 m/s ]
Sahay Sir > Question Answers > then the number of electrons emitted per second per unit area from the surface will be : [Planck constant h=6.64×10^−34 Js; Velocity of light =3×10^8 m/s ]
Light rays of wavelengths 6000A ˚and of photon intensity 39.6 watts/m^2 incidents on a metal surface. If only 1% of photons incident on the surface emit photoelectrons, then the number of electrons emitted per second per unit area from the surface will be : [Planck constant h=6.64×10^−34 Js; Velocity of light =3×10^8 m/s ] Light [...]