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If 92 U^238 undergoes successively 8 alpha decays and 6 beta-decays, then resulting nucleus is

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If 92 U^238 undergoes successively 8 alpha decays and 6 beta-decays, then resulting nucleus is If 92 U^238 undergoes successively 8 alpha decays and 6 beta-decays then resulting nucleus is November 28, 2020 Category: AIIMS Last 24 Years Solved 1996 - 2019 Physics and Chemistry Video Solutions , Chapter 31 - Nuclei , Physics ,

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