then prove that angle BOC = 90°-1/2angle BAC.

Sahay Sir > Question Answers > then prove that angle BOC = 90°-1/2angle BAC.
Example 8 : In Fig.6.38, the sides AB and AC of ∆ABC are produced to point E and D respectively. If bisectors BO and CO of angle CBE and angle BCD respectively meet at point O, then prove that angle BOC = 90°-1/2angle BAC.
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Oct
Example 8 : In Fig.6.38, the sides AB and AC of ∆ABC are produced to point E and D respectively. If bisectors BO and CO of angle CBE and angle BCD respectively meet at point O, then prove that angle BOC = 90°-1/2angle BAC. Example 8 : In Fig.6.38 the sides AB and AC of [...]
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Tags: Example 8 : In Fig.6.38 , the sides AB and AC of ∆ABC are produced to point E and D respectively. If bisectors BO and CO of angle CBE and angle BCD respectively meet at point O , then prove that angle BOC = 90°-1/2angle BAC. ,