then its velocity at a distance of 9 mm from P is : [Take1/4πε0 = 9 × 10^9 Nm^2C^−2]

Sahay Sir > Question Answers > then its velocity at a distance of 9 mm from P is : [Take1/4πε0 = 9 × 10^9 Nm^2C^−2]
In free space, a particle A of charge 1 μC is held fixed at a point P. Another particle B of the same charge and mass 4 μg is kept at a distance of 1 mm from P. if B is released, then its velocity at a distance of 9 mm from P is : [Take1/4πε0 = 9 × 10^9 Nm^2C^−2]
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Dec
In free space, a particle A of charge 1 μC is held fixed at a point P. Another particle B of the same charge and mass 4 μg is kept at a distance of 1 mm from P. if B is released, then its velocity at a distance of 9 mm from P is : [...]
Posted in: Arihant Physics by D.C Pandey , Chapter 2 - Electrostatic Potential and Capacitance , Volume 2 ,
Tags: a particle A of charge 1 μC is held fixed at a point P. Another particle B of the same charge and mass 4 μg is kept at a distance of 1 mm from P. if B is released , In free space , then its velocity at a distance of 9 mm from P is : [Take1/4πε0 = 9 × 10^9 Nm^2C^−2] ,