The work done by a force F→=(−6x^3iˆ) N in displacing a particle from x = 4m to x = – 2m is
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A block of mass 1 kg is projected with initial velocity (V0) of 10 m/s on a rough inclined surface. The block moves up and come back to its initial position and stops. Find the work done by the friction on the block.
28
Oct
A block of mass 1 kg is projected with initial velocity (V0) of 10 m/s on a rough inclined surface. The block moves up and come back to its initial position and stops. Find the work done by the friction on the block. The work done by a force F→=(−6x^3iˆ) N in displacing a particle [...]
A 10 kg block is pulled in the vertical plane along a frictionless surface in the form of an arc or a circle of radius 10m. The applied force is of 200 N as shown in the figure. If the block started from rest at A, the velocity at B would be: (g = 10 m/s^2 )
28
Oct
A 10 kg block is pulled in the vertical plane along a frictionless surface in the form of an arc or a circle of radius 10m. The applied force is of 200 N as shown in the figure. If the block started from rest at A, the velocity at B would be: (g = 10 [...]
A particle starts from origin and moves along a parabolic path whose equation is y=x^2 in the presence of a no. of forces. one of the forces acting on the particle is F=(xî-4zk cap )N. Find work done by this force F when the particle moves from the origin to x = 2m.
28
Oct
A particle starts from origin and moves along a parabolic path whose equation is y=x^2 in the presence of a no. of forces. one of the forces acting on the particle is F=(xî-4zk cap )N. Find work done by this force F when the particle moves from the origin to x = 2m. The work [...]
The work done by a force F→=(−6x^3iˆ) N in displacing a particle from x = 4m to x = – 2m is
28
Oct
The work done by a force F→=(−6x^3iˆ) N in displacing a particle from x = 4m to x = – 2m is The work done by a force F→=(−6x^3iˆ) N in displacing a particle from x = 4m to x = - 2m is October 28, 2020 Category: Chapter 6 - Work, Energy and Power [...]