The volume of the frustum of a cone is 1/3πh[r^21+r^22−r1r2]

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The volume of the frustum of a cone is 1/3πh[r^21+r^22−r1r2], where h is vertical height of the frustum and r1,r2 are the radii of the ends.
25
Nov
The volume of the frustum of a cone is 1/3πh[r^21+r^22−r1r2], where h is vertical height of the frustum and r1,r2 are the radii of the ends. r2 are the radii of the ends. The volume of the frustum of a cone is 1/3πh[r^21+r^22−r1r2] where h is vertical height of the frustum and r1 November 25, [...]
Posted in: Chapter 13 - Surface Areas and Volumes , Maths , NCERT Class 10 ,
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