The trajectory of a projectile in a vertical plane is y=ax −bx^2
The trajectory of a projectile in a vertical plane is y=ax −bx^2, where a, b are constants, and x and y are, respectively, the horizontal and vertical distance of the projectile from the point of projection. The maximum height attained is ________ and the angle of projectile from the horizontal is _______.
05
Sep
The trajectory of a projectile in a vertical plane is y=ax −bx^2, where a, b are constants, and x and y are, respectively, the horizontal and vertical distance of the projectile from the point of projection. The maximum height attained is ________ and the angle of projectile from the horizontal is _______. and x and [...]
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and x and y are ,
b are constants ,
respectively ,
the horizontal and vertical distance of the projectile from the point of projection. The maximum height attained is ________ and the angle of projectile from the horizontal is _______. ,
The trajectory of a projectile in a vertical plane is y=ax −bx^2 ,
Where a ,