The ring shown in Fig. 6.360 is given a constant horizontal acceleration (a0 = g/root 3). The maximum deflection of the string from the vertical is theta 0

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The ring shown in Fig. 6.360 is given a constant horizontal acceleration (a0 = g/root 3). The maximum deflection of the string from the vertical is theta 0, then
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Sep
The ring shown in Fig. 6.360 is given a constant horizontal acceleration (a0 = g/root 3). The maximum deflection of the string from the vertical is theta 0, then The ring shown in Fig. 6.360 is given a constant horizontal acceleration (a0 = g/root 3). The maximum deflection of the string from the vertical is [...]
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