The potential energy of a 1kg particle free to move along the x- axis is given by V(x)=(x^4/4−x^2/2)J The total mechanical energy of the particle is 2J . Then
Sahay Sir > Question Answers > The potential energy of a 1kg particle free to move along the x- axis is given by V(x)=(x^4/4−x^2/2)J The total mechanical energy of the particle is 2J . Then
The potential energy of a 1kg particle free to move along the x- axis is given by V(x)=(x^4/4−x^2/2)J The total mechanical energy of the particle is 2J . Then , the maximum speed (in m/s) is the maximum speed (in m/s) is The potential energy of a 1kg particle free to move along the x- [...]