The potential energy function for a particle executing linear SHM is given by V(x)= 2/1 kx^2 where k is the force constant of the oscillator. For k=0.5 Nm^−1
Sahay Sir > Question Answers > The potential energy function for a particle executing linear SHM is given by V(x)= 2/1 kx^2 where k is the force constant of the oscillator. For k=0.5 Nm^−1
The potential energy function for a particle executing linear SHM is given by V(x)= 2/1 kx^2 where k is the force constant of the oscillator. For k=0.5 Nm^−1, the graph of V(x) versus x is shown in the figure. A particle of total energy E turns back when it reaches x=±x m . [...]