The phase difference between two waves represented by y1​ = 10^−6sin [100t+50x​+0.5]m y2​ = 10^−6cos [100t+50x​]m where x is expressed in metres and t is expressed in seconds is approximately

Sahay Sir > Question Answers > The phase difference between two waves represented by y1​ = 10^−6sin [100t+50x​+0.5]m y2​ = 10^−6cos [100t+50x​]m where x is expressed in metres and t is expressed in seconds is approximately
The phase difference between two waves represented by y1​ = 10^−6sin [100t+50x​+0.5]m y2​ = 10^−6cos [100t+50x​]m where x is expressed in metres and t is expressed in seconds is approximately
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Aug
The phase difference between two waves represented by y1​ = 10^−6sin [100t+50x​+0.5]m y2​ = 10^−6cos [100t+50x​]m where x is expressed in metres and t is expressed in seconds is approximately The phase difference between two waves represented by y1​ = 10^−6sin [100t+50x​+0.5]m y2​ = 10^−6cos [100t+50x​]m where x is expressed in metres and t is [...]
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