The perpendicular from A on side BC of a ΔABC intersect BC at D such that DB = 3CD. Prove that 2AB^2 = 2AC^2 + BC^2.

Sahay Sir > Question Answers > The perpendicular from A on side BC of a ΔABC intersect BC at D such that DB = 3CD. Prove that 2AB^2 = 2AC^2 + BC^2.
The perpendicular from A on side BC of a ΔABC intersect BC at D such that DB = 3CD. Prove that 2AB^2 = 2AC^2 + BC^2.
05
Oct
The perpendicular from A on side BC of a ΔABC intersect BC at D such that DB = 3CD. Prove that 2AB^2 = 2AC^2 + BC^2. The perpendicular from A on side BC of a ΔABC intersect BC at D such that DB = 3CD. Prove that 2AB^2 = 2AC^2 + BC^2. October 5, 2020 [...]
Posted in: Chapter 6 - Triangles , Maths , NCERT Class 10 ,
Tags: The perpendicular from A on side BC of a ΔABC intersect BC at D such that DB = 3CD. Prove that 2AB^2 = 2AC^2 + BC^2. ,