the percentage error in the value of E(t) at t = 5 s` is
Column II shows five systems in which two object are labelled as X and Y. Also in each case a point P is shown. Column I gives some statements about X and/or Y. Match these statements to the appropriate system(s) from Column II.
12
Feb
Column II shows five systems in which two object are labelled as X and Y. Also in each case a point P is shown. Column I gives some statements about X and/or Y. Match these statements to the appropriate system(s) from Column II. The energy of a system as a function of time t is [...]
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The energy of a system as a function of time t is given as E(t)=A^2 exp(−αt) ,
the percentage error in the value of E(t) at t = 5 s` is ,
The pitch of a screw gauge is 1 mm and there are 100 divisions on the circular scale. While measuring the diameter of a wire ,
α=0.2 s−1. The measurement of A has an error of 1.25%. If the error In the measurement of time is 1.50% ,
Column II gives certain systems undergoing a process. Column I suggests changes in some of the parameters related to the system. Match the statements in Column I to the appropriate process(es) from Column II
12
Feb
Column II gives certain systems undergoing a process. Column I suggests changes in some of the parameters related to the system. Match the statements in Column I to the appropriate process(es) from Column II The energy of a system as a function of time t is given as E(t)=A^2 exp(−αt) the percentage error in the [...]
Tags:
The energy of a system as a function of time t is given as E(t)=A^2 exp(−αt) ,
the percentage error in the value of E(t) at t = 5 s` is ,
The pitch of a screw gauge is 1 mm and there are 100 divisions on the circular scale. While measuring the diameter of a wire ,
α=0.2 s−1. The measurement of A has an error of 1.25%. If the error In the measurement of time is 1.50% ,
The pitch of a screw gauge is 1 mm and there are 100 divisions on the circular scale. While measuring the diameter of a wire, the linear scale reads 1 mm and 47th division on the circular scale coincides with the reference line. The length of the wire is 5.6 cm. Find the curved surface area (in cm ^2) of the wire in appropriate number of significant figures.
12
Feb
The pitch of a screw gauge is 1 mm and there are 100 divisions on the circular scale. While measuring the diameter of a wire, the linear scale reads 1 mm and 47th division on the circular scale coincides with the reference line. The length of the wire is 5.6 cm. Find the curved surface [...]
Tags:
The energy of a system as a function of time t is given as E(t)=A^2 exp(−αt) ,
the percentage error in the value of E(t) at t = 5 s` is ,
The pitch of a screw gauge is 1 mm and there are 100 divisions on the circular scale. While measuring the diameter of a wire ,
α=0.2 s−1. The measurement of A has an error of 1.25%. If the error In the measurement of time is 1.50% ,
A steel wire of diameter 0.5 mm and Young’s modulus 2 × 10^11 N m^–2 carries a load of mass M. The length of the wire with the load is 1.0 m. A vernier scale with 10 divisions is attached to the end of this wire. Next to the steel wire is a reference wire to which a main scale, of least count 1.0 mm, is attached. The 10 divisions of the vernier scale correspond to 9 divisions of the main scale. Initially, the zero of vernier scale coincides with the zero of main scale. If the load on the steel wire is increased by 1.2 kg, the vernier scale division which coincides with a main scale division is.(Take g = 10 ms–2 and π = 3.2).
12
Feb
A steel wire of diameter 0.5 mm and Young’s modulus 2 × 10^11 N m^–2 carries a load of mass M. The length of the wire with the load is 1.0 m. A vernier scale with 10 divisions is attached to the end of this wire. Next to the steel wire is a reference wire [...]
The energy of a system as a function of time t is given as E(t)=A^2 exp(−αt), α=0.2 s−1. The measurement of A has an error of 1.25%. If the error In the measurement of time is 1.50%, the percentage error in the value of E(t) at t = 5 s` is
12
Feb
The energy of a system as a function of time t is given as E(t)=A^2 exp(−αt), α=0.2 s−1. The measurement of A has an error of 1.25%. If the error In the measurement of time is 1.50%, the percentage error in the value of E(t) at t = 5 s` is The energy of a [...]