the mass of water present will be [Take specific heat of water = 1 cal g^-1°C^-1 and latent heat of steam = 540 cal g^-1]

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Steam at 100°C is passed into 20 g of water at 10°C. When water acquires a temperature of 80°C, the mass of water present will be [Take specific heat of water = 1 cal g^-1°C^-1 and latent heat of steam = 540 cal g^-1]
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Aug
Steam at 100°C is passed into 20 g of water at 10°C. When water acquires a temperature of 80°C, the mass of water present will be [Take specific heat of water = 1 cal g^-1°C^-1 and latent heat of steam = 540 cal g^-1] Steam at 100°C is passed into 20 g of water at [...]
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Tags: Steam at 100°C is passed into 20 g of water at 10°C. When water acquires a temperature of 80°C , the mass of water present will be [Take specific heat of water = 1 cal g^-1°C^-1 and latent heat of steam = 540 cal g^-1] ,