the magnitude of the current in each wire and the direction of the magnetic field at O will be (μ0 = 4p × 10^–7 NA^–2) :
Sahay Sir > Question Answers > the magnitude of the current in each wire and the direction of the magnetic field at O will be (μ0 = 4p × 10^–7 NA^–2) :
As shown in the figure, two infinitely long, identical wires are bent by 90º and placed in such a way that the segments LP and QM are along the x-axis, while segments PS and QN are parallel to the y-axis. If OP = OQ = 4cm, and the magnitude of the magnetic field at O is 10^–4T, and the two wires carry equal currents (see figure), the magnitude of the current in each wire and the direction of the magnetic field at O will be (μ0 = 4p × 10^–7 NA^–2) :
21
Nov
As shown in the figure, two infinitely long, identical wires are bent by 90º and placed in such a way that the segments LP and QM are along the x-axis, while segments PS and QN are parallel to the y-axis. If OP = OQ = 4cm, and the magnitude of the magnetic field at O [...]
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and the magnitude of the magnetic field at O is 10^–4T ,
and the two wires carry equal currents (see figure) ,
As shown in the figure ,
identical wires are bent by 90º and placed in such a way that the segments LP and QM are along the x-axis ,
the magnitude of the current in each wire and the direction of the magnetic field at O will be (μ0 = 4p × 10^–7 NA^–2) : ,
Two infinitely long ,
while segments PS and QN are parallel to the y-axis. If OP = OQ = 4cm ,