The magnetic field of a beam emerging from a filter facing a flood light as given by B=12×10^−8 sin(1.20×10^7 z−3.6×10^15 t) The average intensity of the beam is

Sahay Sir > Question Answers > The magnetic field of a beam emerging from a filter facing a flood light as given by B=12×10^−8 sin(1.20×10^7 z−3.6×10^15 t) The average intensity of the beam is
The magnetic field of a beam emerging from a filter facing a flood light as given by B=12×10^−8 sin(1.20×10^7 z−3.6×10^15 t) The average intensity of the beam is
04
Sep
The magnetic field of a beam emerging from a filter facing a flood light as given by B=12×10^−8 sin(1.20×10^7 z−3.6×10^15 t) The average intensity of the beam is The magnetic field of a beam emerging from a filter facing a flood light as given by B=12×10^−8 sin(1.20×10^7 z−3.6×10^15 t) The average intensity of the beam [...]
Posted in: Chapter 8 - Electromagnetic Waves , MTG NEET Physics , Part 2 ,
Tags: The magnetic field of a beam emerging from a filter facing a flood light as given by B=12×10^−8 sin(1.20×10^7 z−3.6×10^15 t) The average intensity of the beam is ,