The instantaneous angular position of a point on a rotating wheel is given by the equation Q(t)=2t^3 − 6t^2. The torque on the wheel becomes zero at :
Sahay Sir > Question Answers > The instantaneous angular position of a point on a rotating wheel is given by the equation Q(t)=2t^3 − 6t^2. The torque on the wheel becomes zero at :
A uniform rod of length l and mass m is free to rotate in a vertical plane about A. The rod initially in horizontal position is released. The initial angular acceleration of the rod is (Moment of inertia of rod about A is 3/ml^2.)
29
Aug
A uniform rod of length l and mass m is free to rotate in a vertical plane about A. The rod initially in horizontal position is released. The initial angular acceleration of the rod is (Moment of inertia of rod about A is 3/ml^2.) The instantaneous angular position of a point on a rotating wheel [...]
The instantaneous angular position of a point on a rotating wheel is given by the equation Q(t)=2t^3 − 6t^2. The torque on the wheel becomes zero at :
29
Aug
The instantaneous angular position of a point on a rotating wheel is given by the equation Q(t)=2t^3 − 6t^2. The torque on the wheel becomes zero at : The instantaneous angular position of a point on a rotating wheel is given by the equation Q(t)=2t^3 − 6t^2. The torque on the wheel becomes zero at [...]