The equation of projectile is y = ax – bx^2 where a and b are the constants. Its horizontal range is

Sahay Sir > Question Answers > The equation of projectile is y = ax - bx^2 where a and b are the constants. Its horizontal range is
The equation of projectile is y = ax – bx^2 where a and b are the constants. Its horizontal range is
10
Sep
The equation of projectile is y = ax – bx^2 where a and b are the constants. Its horizontal range is The equation of projectile is y = ax - bx^2 where a and b are the constants. Its horizontal range is September 10, 2020 Category: Chapter 4 - Motion in Plane , MTG NEET [...]
Posted in: Chapter 4 - Motion in Plane , MTG NEET Physics , Part 1 ,
Tags: The equation of projectile is y = ax - bx^2 where a and b are the constants. Its horizontal range is ,