The equation of projectile is y = 16x – 5x^2/4. Find the horizontal range.

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The equation of projectile is y = 16x – 5x^2/4. Find the horizontal range.
19
Sep
The equation of projectile is y = 16x – 5x^2/4. Find the horizontal range. The equation of projectile is y = 16x - 5x^2/4. Find the horizontal range. September 19, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,
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