the distance between the slits is halved and the wavelength of light changed from 6.4×10^−7 m to 4.0×10^−7 m

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In Young’s double-slit experiment the distance between the centres of the adjacent fringes is 0.10 mm. If the distance of the screen from the slits is doubled, the distance between the slits is halved and the wavelength of light changed from 6.4×10^−7 m to 4.0×10^−7 m, then what is the new distance between the fringes?(in mm)
09
Nov
In Young’s double-slit experiment the distance between the centres of the adjacent fringes is 0.10 mm. If the distance of the screen from the slits is doubled, the distance between the slits is halved and the wavelength of light changed from 6.4×10^−7 m to 4.0×10^−7 m, then what is the new distance between the fringes?(in [...]
Posted in: Chapter 10 - Wave Optics , MTG NEET Physics , Part 2 ,
Tags: In Young's double-slit experiment the distance between the centres of the adjacent fringes is 0.10 mm. If the distance of the screen from the slits is doubled , the distance between the slits is halved and the wavelength of light changed from 6.4×10^−7 m to 4.0×10^−7 m , then what is the new distance between the fringes?(in mm) ,