The curved surface area of frustum of a cone is π/(r1+r2)

Sahay Sir > Question Answers > The curved surface area of frustum of a cone is π/(r1+r2)
The curved surface area of frustum of a cone is π/(r1+r2), where l = h^2 + (r1+r2)^2−−√,r1 and r2 are the radii of two ends of the frustum and h s the vertical height.
25
Nov
The curved surface area of frustum of a cone is π/(r1+r2), where l = h^2 + (r1+r2)^2−−√,r1 and r2 are the radii of two ends of the frustum and h s the vertical height. r1 and r2 are the radii of two ends of the frustum and h s the vertical height. The curved surface [...]
Posted in: Chapter 13 - Surface Areas and Volumes , Maths , NCERT Class 10 ,
Tags: r1 and r2 are the radii of two ends of the frustum and h s the vertical height. , The curved surface area of frustum of a cone is π/(r1+r2) , where l = h^2 + (r1+r2)^2−−√ ,