the acceleration of A is aA = 15i + 15j. Then the acceleration of B is

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A bob is hanging over a pulley inside a car through a string. The second end of the string is in the hands of a person standing in the car. The car is moving with constant acceleration a directed horizontally
29
Sep
A bob is hanging over a pulley inside a car through a string. The second end of the string is in the hands of a person standing in the car. The car is moving with constant acceleration a directed horizontally In Fig. 6.347 the acceleration of A is aA = 15i + 15j. Then the [...]
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Tags: In Fig. 6.347 , the acceleration of A is aA = 15i + 15j. Then the acceleration of B is ,
In Fig. 6.347, the acceleration of A is aA = 15i + 15j. Then the acceleration of B is
29
Sep
In Fig. 6.347, the acceleration of A is aA = 15i + 15j. Then the acceleration of B is In Fig. 6.347 the acceleration of A is aA = 15i + 15j. Then the acceleration of B is September 29, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,
Posted in: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) ,
Tags: In Fig. 6.347 , the acceleration of A is aA = 15i + 15j. Then the acceleration of B is ,