suppose there are 3.0 * 10^7 radon atoms (T 1/2 = 3.83 days or 3.31 * 10^5 s) trapped in a basement. (a) How many radon atoms remain after 31 days? (b) Find the activity

Sahay Sir > Question Answers > suppose there are 3.0 * 10^7 radon atoms (T 1/2 = 3.83 days or 3.31 * 10^5 s) trapped in a basement. (a) How many radon atoms remain after 31 days? (b) Find the activity
In the above illustration, suppose there are 3.0 * 10^7 radon atoms (T 1/2 = 3.83 days or 3.31 * 10^5 s) trapped in a basement. (a) How many radon atoms remain after 31 days? (b) Find the activity
12
Sep
In the above illustration, suppose there are 3.0 * 10^7 radon atoms (T 1/2 = 3.83 days or 3.31 * 10^5 s) trapped in a basement. (a) How many radon atoms remain after 31 days? (b) Find the activity In the above illustration suppose there are 3.0 * 10^7 radon atoms (T 1/2 = 3.83 [...]
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Tags: In the above illustration , suppose there are 3.0 * 10^7 radon atoms (T 1/2 = 3.83 days or 3.31 * 10^5 s) trapped in a basement. (a) How many radon atoms remain after 31 days? (b) Find the activity ,