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show that ar (AGB) = ar (AGC) = ar (BGC) = 1/3 ar (ABC)
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show that ar (AGB) = ar (AGC) = ar (BGC) = 1/3 ar (ABC)
8. If the medians of a ∆ ABC intersect at G, show that ar (AGB) = ar (AGC) = ar (BGC) = 1/3 ar (ABC)
01
Jul
8. If the medians of a ∆ ABC intersect at G, show that ar (AGB) = ar (AGC) = ar (BGC) = 1/3 ar (ABC) 8. If the medians of a ∆ ABC intersect at G show that ar (AGB) = ar (AGC) = ar (BGC) = 1/3 ar (ABC) July 1, 2021 Category: Chapter [...]
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Chapter 9 - Areas of Parallelogram and Triangles
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Maths
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NCERT Class 9
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8. If the medians of a ∆ ABC intersect at G
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show that ar (AGB) = ar (AGC) = ar (BGC) = 1/3 ar (ABC)
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