respectively. The system hangs freely in equilibrium with ends A and E of the string fixed in the same horizontal line. it is given that tanα=3/4 and tanβ=12/5. Then the tension in the string BC is

Sahay Sir > Question Answers > respectively. The system hangs freely in equilibrium with ends A and E of the string fixed in the same horizontal line. it is given that tanα=3/4 and tanβ=12/5. Then the tension in the string BC is
Figure, represents a light inextensible string ABCDE in which AB=BC=CD=DE and to which are attached masses M, m, and M at the point B,C and D, respectively. The system hangs freely in equilibrium with ends A and E of the string fixed in the same horizontal line. it is given that tanα=3/4 and tanβ=12/5. Then the tension in the string BC is
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Oct
Figure, represents a light inextensible string ABCDE in which AB=BC=CD=DE and to which are attached masses M, m, and M at the point B,C and D, respectively. The system hangs freely in equilibrium with ends A and E of the string fixed in the same horizontal line. it is given that tanα=3/4 and tanβ=12/5. Then [...]
Posted in: Cengage JEE Mains Physics by B.M Sharma , Chapter 5 - Newton's Laws of Motion (Without Friction) ,
Tags: and M at the point B , C and D , Figure , m , represents a light inextensible string ABCDE in which AB=BC=CD=DE and to which are attached masses M , respectively. The system hangs freely in equilibrium with ends A and E of the string fixed in the same horizontal line. it is given that tanα=3/4 and tanβ=12/5. Then the tension in the string BC is ,