Prove that sec^2θ + cosec^2θ−−√ = tanθ + cot θ
The lower window of a house is at a height of 2 m above the ground and its upper window is 4 m vertically above the lower window. At certain instant the angles of elevation of a balloon from these windows are observed to be 60° and 30°, respectively. Find the height of the balloon above the ground.
25
Nov
The lower window of a house is at a height of 2 m above the ground and its upper window is 4 m vertically above the lower window. At certain instant the angles of elevation of a balloon from these windows are observed to be 60° and 30°, respectively. Find the height of the balloon [...]
A ladder rests against a vertical wall at an inclination α to the horizontal. Its foot is pulled away from the wall through a distance p so that its upper end slides a distance q down the wall and then the ladder makes an angle β to the horizontal. Show that p/q = cosβ − cosα / sinα − sinβ
25
Nov
A ladder rests against a vertical wall at an inclination α to the horizontal. Its foot is pulled away from the wall through a distance p so that its upper end slides a distance q down the wall and then the ladder makes an angle β to the horizontal. Show that p/q = cosβ − [...]
The angle of elevation of the top of a tower 30 m high from the foot of another tower in the same plane is 60° and the angle of elevation of the top of the second tower from the foot of the first tower is 30°. Find the distance between the two towers and also the height of the other tower.
25
Nov
The angle of elevation of the top of a tower 30 m high from the foot of another tower in the same plane is 60° and the angle of elevation of the top of the second tower from the foot of the first tower is 30°. Find the distance between the two towers and also [...]
Prove that sec^2θ + cosec^2θ−−√ = tanθ + cot θ
25
Nov
Prove that sec^2θ + cosec^2θ−−√ = tanθ + cot θ Prove that sec^2θ + cosec^2θ−−√ = tanθ + cot θ November 25, 2020 Category: Chapter 8 - Introduction to Trigonometry , Maths , NCERT Class 10 ,